(2x^-3/3y^-4)^-2

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Solution for (2x^-3/3y^-4)^-2 equation: 


D( x )

x = 0

((2*x^-3)/3)*y^-4 = 0

x = 0

x = 0

((2*x^-3)/3)*y^-4 = 0

((2*x^-3)/3)*y^-4 = 0

2/3*x^-3*y^-4 = 0 // : 2/3*y^-4

x^-3 = 0

x naleu017Cy do O

x in (-oo:0) U (0:+oo)

(((2*x^-3)/3)*y^-4)^-2 = 0

9/4*x^6*y^8 = 0 // : 9/4*y^8

x^6 = 0

x = 0

x in { 0} 

x belongs to the empty set

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